24.5t+2-4.9t^2=0

Solution for 24.5t+2-4.9t^2=0 equation:

24.5t+2-4.9t^2=0

a = -4.9; b = 24.5; c = +2;
Δ = b2-4ac
Δ = 24.52-4·(-4.9)·2
Δ = 639.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24.5)-\sqrt{639.45}}{2*-4.9}=\frac{-24.5-\sqrt{639.45}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24.5)+\sqrt{639.45}}{2*-4.9}=\frac{-24.5+\sqrt{639.45}}{-9.8}
$